Question
.In a particular area, the density of water vapor in the air is 9 g/cm3. The saturation density is 18 g/cm3. What is the humidity?
(10 Points)
A . 25%
B. 50 %
C. 9 g/cm3
D. 27 g/cm3
(10 Points)
A . 25%
B. 50 %
C. 9 g/cm3
D. 27 g/cm3
Answers
GPT-4o mini
To calculate the humidity, we use the formula:
\[
\text{Humidity} = \left( \frac{\text{Density of water vapor}}{\text{Saturation density}} \right) \times 100\%
\]
Given:
- Density of water vapor = 9 g/cm³
- Saturation density = 18 g/cm³
Substituting these values into the formula:
\[
\text{Humidity} = \left( \frac{9 \, \text{g/cm}^3}{18 \, \text{g/cm}^3} \right) \times 100\% = 0.5 \times 100\% = 50\%
\]
Thus, the humidity is **50%**.
The correct answer is **B. 50%**.
\[
\text{Humidity} = \left( \frac{\text{Density of water vapor}}{\text{Saturation density}} \right) \times 100\%
\]
Given:
- Density of water vapor = 9 g/cm³
- Saturation density = 18 g/cm³
Substituting these values into the formula:
\[
\text{Humidity} = \left( \frac{9 \, \text{g/cm}^3}{18 \, \text{g/cm}^3} \right) \times 100\% = 0.5 \times 100\% = 50\%
\]
Thus, the humidity is **50%**.
The correct answer is **B. 50%**.