Question

which subnet address would include address 192.168.1.88/27 as usable host address .give broadcast and subnet mask

Answer 1

To determine the subnet information for the IP address 192.168.1.88 with a /27 subnet mask, we can break it down as follows:

1. **Subnet Mask**:
A /27 subnet mask means that the first 27 bits are the network portion, which translates to a subnet mask of:
- In decimal: 255.255.255.224
- In binary: 11111111.11111111.11111111.11111100

2. **Network Address**:
To find the network address, we perform a bitwise AND operation between the IP address and the subnet mask:
- IP Address: 192.168.1.88 -> 11000000.10101000.00000001.01011000
- Subnet Mask: 255.255.255.224 -> 11111111.11111111.11111111.11111100
- Performing the AND operation:

```
11000000.10101000.00000001.01011000
AND
11111111.11111111.11111111.11111100
-------------------------------------
11000000.10101000.00000001.01010000
```

- The result in decimal is 192.168.1.80. Therefore, the **network address** is 192.168.1.80.

3. **Broadcast Address**:
The broadcast address can be calculated by taking the network address and setting all host bits (the remaining bits after the network portion) to 1. For a /27 subnet, there are 32 - 27 = 5 host bits.
- The network address is 192.168.1.80, or in binary:
```
11000000.10101000.00000001.01010000
```
- The broadcast address has the same network portion and the last 5 bits set to 1:
```
11000000.10101000.00000001.01011111
```
- In decimal, this is 192.168.1.95. Therefore, the **broadcast address** is 192.168.1.95.

4. **Usable Host Addresses**:
The usable host addresses range from the first IP after the network address to the one before the broadcast address:
- First usable host: 192.168.1.81
- Last usable host: 192.168.1.94

### Summary:
- **Network Address**: 192.168.1.80
- **Broadcast Address**: 192.168.1.95
- **Subnet Mask**: 255.255.255.224 (or /27)
- **Usable Host Range**: 192.168.1.81 to 192.168.1.94