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Given a point on a line segment (-4, 5) what is the new point when the point is rotated counterclockwise about the origin 270 d...Asked by bakugo
Given a point on a line segment (−4, 5)
, what is the new point when the point is rotated counterclockwise about the origin 270 degrees
, what is the new point when the point is rotated counterclockwise about the origin 270 degrees
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GPT-4o mini
To rotate a point counterclockwise about the origin, we can use the rotation formula. For a given point \((x, y)\) and an angle of \(\theta\), the new coordinates \((x', y')\) after rotation can be calculated using the following equations:
\[
x' = x \cdot \cos(\theta) - y \cdot \sin(\theta)
\]
\[
y' = x \cdot \sin(\theta) + y \cdot \cos(\theta)
\]
In this case, the angle \(\theta\) is 270 degrees.
First, we need to find the cosine and sine of 270 degrees:
- \(\cos(270^\circ) = 0\)
- \(\sin(270^\circ) = -1\)
Now, we can substitute the point \((-4, 5)\) into the rotation formulas:
\[
x' = -4 \cdot 0 - 5 \cdot (-1) = 0 + 5 = 5
\]
\[
y' = -4 \cdot (-1) + 5 \cdot 0 = 4 + 0 = 4
\]
Thus, the new coordinates after rotating the point \((-4, 5)\) counterclockwise about the origin by 270 degrees are \((5, 4)\).
\[
x' = x \cdot \cos(\theta) - y \cdot \sin(\theta)
\]
\[
y' = x \cdot \sin(\theta) + y \cdot \cos(\theta)
\]
In this case, the angle \(\theta\) is 270 degrees.
First, we need to find the cosine and sine of 270 degrees:
- \(\cos(270^\circ) = 0\)
- \(\sin(270^\circ) = -1\)
Now, we can substitute the point \((-4, 5)\) into the rotation formulas:
\[
x' = -4 \cdot 0 - 5 \cdot (-1) = 0 + 5 = 5
\]
\[
y' = -4 \cdot (-1) + 5 \cdot 0 = 4 + 0 = 4
\]
Thus, the new coordinates after rotating the point \((-4, 5)\) counterclockwise about the origin by 270 degrees are \((5, 4)\).
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