Asked by bakugo
Given a point ( x, y
), what is the new point when the point is rotated counterclockwise about the origin 270 degrees
), what is the new point when the point is rotated counterclockwise about the origin 270 degrees
Answers
Answered by
bakugo
Given a point on a geometric figure (1, 2)
, what is the new point when the point is rotated clockwise about the origin 90 degrees
, what is the new point when the point is rotated clockwise about the origin 90 degrees
Answered by
GPT-4o mini
To rotate a point \((x, y)\) counterclockwise about the origin by \(270\) degrees, you can use the rotation formula. The general formula for rotating a point \((x, y)\) counterclockwise by an angle \(\theta\) is given by:
\[
(x', y') = (x \cos \theta - y \sin \theta, x \sin \theta + y \cos \theta)
\]
For a rotation of \(270\) degrees, we convert this angle to radians:
\[
270 \text{ degrees} = \frac{270 \pi}{180} = \frac{3\pi}{2} \text{ radians}
\]
Next, we evaluate \(\cos(270^\circ)\) and \(\sin(270^\circ)\):
- \(\cos(270^\circ) = 0\)
- \(\sin(270^\circ) = -1\)
Substituting these values into the rotation formula:
\[
(x', y') = (x \cdot 0 - y \cdot (-1), x \cdot (-1) + y \cdot 0)
\]
This simplifies to:
\[
(x', y') = (y, -x)
\]
So, the new point after rotating the point \((x, y)\) counterclockwise by \(270\) degrees about the origin is:
\[
(y, -x)
\]
\[
(x', y') = (x \cos \theta - y \sin \theta, x \sin \theta + y \cos \theta)
\]
For a rotation of \(270\) degrees, we convert this angle to radians:
\[
270 \text{ degrees} = \frac{270 \pi}{180} = \frac{3\pi}{2} \text{ radians}
\]
Next, we evaluate \(\cos(270^\circ)\) and \(\sin(270^\circ)\):
- \(\cos(270^\circ) = 0\)
- \(\sin(270^\circ) = -1\)
Substituting these values into the rotation formula:
\[
(x', y') = (x \cdot 0 - y \cdot (-1), x \cdot (-1) + y \cdot 0)
\]
This simplifies to:
\[
(x', y') = (y, -x)
\]
So, the new point after rotating the point \((x, y)\) counterclockwise by \(270\) degrees about the origin is:
\[
(y, -x)
\]