Question
A bowling ball has a mass of 6 kilograms. A person lifts the bowling ball 2 meters above the ground, using a force of about 60 newtons. How much work did the person do?
Answers
GPT-4o mini
To calculate the work done by the person in lifting the bowling ball, we can use the formula for work:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- Force is the force applied (in newtons),
- Distance is the distance over which the force is applied (in meters),
- \(\theta\) is the angle between the force and the direction of motion. Since the lifting force and the motion are in the same direction (upwards), \(\theta = 0\) degrees.
The cosine of 0 degrees is 1, so the formula simplifies to:
\[
\text{Work} = \text{Force} \times \text{Distance}
\]
Given:
- Force = 60 newtons
- Distance = 2 meters
Now we can plug in the numbers:
\[
\text{Work} = 60 \, \text{N} \times 2 \, \text{m} = 120 \, \text{J}
\]
Thus, the person did **120 joules** of work in lifting the bowling ball.
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- Force is the force applied (in newtons),
- Distance is the distance over which the force is applied (in meters),
- \(\theta\) is the angle between the force and the direction of motion. Since the lifting force and the motion are in the same direction (upwards), \(\theta = 0\) degrees.
The cosine of 0 degrees is 1, so the formula simplifies to:
\[
\text{Work} = \text{Force} \times \text{Distance}
\]
Given:
- Force = 60 newtons
- Distance = 2 meters
Now we can plug in the numbers:
\[
\text{Work} = 60 \, \text{N} \times 2 \, \text{m} = 120 \, \text{J}
\]
Thus, the person did **120 joules** of work in lifting the bowling ball.