Question

What is the starting value in the equation f(x) =11(1.7)^x-1?

Answer 1

In the equation \( f(x) = 11(1.7)^{x-1} \), the starting value refers to the value of the function when \( x = 0 \).

To find the starting value (initial value), substitute \( x = 0 \) into the function:

\[
f(0) = 11(1.7)^{0-1} = 11(1.7)^{-1}
\]

Calculating \( (1.7)^{-1} \):

\[
(1.7)^{-1} = \frac{1}{1.7}
\]

So,

\[
f(0) = 11 \times \frac{1}{1.7} = \frac{11}{1.7}
\]

Now, performing the division:

\[
\frac{11}{1.7} \approx 6.47
\]

Thus, the starting value (initial value) of the function \( f(x) \) when \( x = 0 \) is approximately \( 6.47 \).