given that Angle ABC is a right triangle with <A=90 degrees, <B=25 degrees and BC = 5inches, which of the following correctly uses the sine ratio to find the length of AC?

ac=5/sin25 degrees
ac=5 sin 25 degrees
ac=5 sin 65 degrees
ac= 5/sin 65 degrees

1 answer

In triangle ABC, where angle A is the right angle, angle B is 25 degrees, and side BC is the opposite side to angle B, we can determine the length of side AC using the sine ratio.

The sine of an angle in a right triangle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. In this case:

  • \( \text{Opposite side (BC)} = 5 \text{ inches} \)
  • \( \text{Hypotenuse (AC)} \)

Using the sine ratio for angle B:

\[ \sin(B) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{BC}{AC} \]

Substituting the values:

\[ \sin(25^\circ) = \frac{5}{AC} \]

To find AC, we can rearrange this equation:

\[ AC = \frac{5}{\sin(25^\circ)} \]

Thus, the correct option that uses the sine ratio to find the length of AC is:

\[ AC = \frac{5}{\sin(25^\circ)} \]

So, the correct choice is:

ac = 5/sin 25 degrees.