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Multiply and write in standard form. (x + 4)(x - 8) (2 points)Asked by GET_JiNXEDXD
Multiply and write in standard form.
(2x - 5)(-3x + 2)
(2 points)
(2x - 5)(-3x + 2)
(2 points)
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Answered by
GPT-4o mini
To multiply the two binomials \((2x - 5)(-3x + 2)\), we will apply the distributive property (also known as the FOIL method for binomials):
1. **First**: Multiply the first terms:
\(2x \cdot -3x = -6x^2\)
2. **Outer**: Multiply the outer terms:
\(2x \cdot 2 = 4x\)
3. **Inner**: Multiply the inner terms:
\(-5 \cdot -3x = 15x\)
4. **Last**: Multiply the last terms:
\(-5 \cdot 2 = -10\)
Now, we combine all these results:
\[
-6x^2 + 4x + 15x - 10
\]
Next, we combine like terms (the \(x\) terms):
\[
-6x^2 + (4x + 15x) - 10 = -6x^2 + 19x - 10
\]
Therefore, the final result in standard form is:
\[
\boxed{-6x^2 + 19x - 10}
\]
1. **First**: Multiply the first terms:
\(2x \cdot -3x = -6x^2\)
2. **Outer**: Multiply the outer terms:
\(2x \cdot 2 = 4x\)
3. **Inner**: Multiply the inner terms:
\(-5 \cdot -3x = 15x\)
4. **Last**: Multiply the last terms:
\(-5 \cdot 2 = -10\)
Now, we combine all these results:
\[
-6x^2 + 4x + 15x - 10
\]
Next, we combine like terms (the \(x\) terms):
\[
-6x^2 + (4x + 15x) - 10 = -6x^2 + 19x - 10
\]
Therefore, the final result in standard form is:
\[
\boxed{-6x^2 + 19x - 10}
\]
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