Question
A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.
Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?
(1 point)
Responses
120p−22≥50
120 p minus 22 is greater than or equal to 50
120p−22<50
120p−22<50
120p−22>50
120 p minus 22 is greater than 50
120p−22≤50
120 p minus 22 is less than or equal to 50
Question 2
(1 point)
The class should sell each cookie for
$0.60.
Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?
(1 point)
Responses
120p−22≥50
120 p minus 22 is greater than or equal to 50
120p−22<50
120p−22<50
120p−22>50
120 p minus 22 is greater than 50
120p−22≤50
120 p minus 22 is less than or equal to 50
Question 2
(1 point)
The class should sell each cookie for
$0.60.
Answers
GPT-4o mini
To determine the possible prices (p) the class can sell the cookies for to reach its goal of making at least $50, we need to account for the total revenue from selling the cookies and subtract the costs.
The total revenue from selling the cookies is given by the number of cookies (120) times the price per cookie (p), which is \(120p\). The class spent $22 on supplies, so to find the net revenue, we subtract the costs:
Net revenue = Total revenue - Costs = \(120p - 22\).
The class wants this net revenue to be at least $50, which can be expressed as the inequality:
\[120p - 22 \geq 50.\]
So the correct inequality is:
**120p - 22 ≥ 50.**
For Question 2, to determine the price per cookie when the class sells each cookie for $0.60, we substitute \(p = 0.60\) into the inequality to check if it meets the goal:
1. Calculate total revenue:
\(120p = 120 \times 0.60 = 72\).
2. Calculate net revenue:
Net revenue = Total revenue - Costs = \(72 - 22 = 50\).
Since the net revenue equals $50, selling each cookie for $0.60 meets the fundraising goal.
Thus, the class can sell each cookie for **$0.60**.
The total revenue from selling the cookies is given by the number of cookies (120) times the price per cookie (p), which is \(120p\). The class spent $22 on supplies, so to find the net revenue, we subtract the costs:
Net revenue = Total revenue - Costs = \(120p - 22\).
The class wants this net revenue to be at least $50, which can be expressed as the inequality:
\[120p - 22 \geq 50.\]
So the correct inequality is:
**120p - 22 ≥ 50.**
For Question 2, to determine the price per cookie when the class sells each cookie for $0.60, we substitute \(p = 0.60\) into the inequality to check if it meets the goal:
1. Calculate total revenue:
\(120p = 120 \times 0.60 = 72\).
2. Calculate net revenue:
Net revenue = Total revenue - Costs = \(72 - 22 = 50\).
Since the net revenue equals $50, selling each cookie for $0.60 meets the fundraising goal.
Thus, the class can sell each cookie for **$0.60**.