In the chemical reaction \( 2H_2 + O_2 \rightarrow 2H_2O \), there are 4 hydrogen (H) atoms present before the reaction (from 2 molecules of \( H_2 \), since each \( H_2 \) molecule has 2 hydrogen atoms).
After the reaction, the products are 2 molecules of water (\( 2H_2O \)). Each water molecule contains 2 hydrogen atoms, so:
\[ 2H_2O \text{ has } 2 \times 2 = 4 \text{ hydrogen atoms.} \]
Therefore, there are 4 hydrogen atoms present after the reaction.
The answer is 4.