To find how much each box of books can weigh without exceeding the maximum weight of the elevator, we start by determining the total weight capacity.
- The maximum weight capacity of the elevator is 2000 pounds.
- Lionel's weight is 170 pounds.
- The total weight of the boxes and Lionel combined should not exceed 2000 pounds.
Let's denote the weight of each box of books as \( x \). Since there are 10 boxes, the total weight of the boxes is \( 10x \).
We set up an inequality:
\[ 10x + 170 \leq 2000 \]
Next, we isolate \( x \):
\[ 10x \leq 2000 - 170 \] \[ 10x \leq 1830 \] \[ x \leq \frac{1830}{10} \] \[ x \leq 183 \]
This means each box of books can weigh up to a maximum of 183 pounds.
Now, we represent this solution on a number line. The range of potential weights for each box is from 0 to 183 (inclusive).
Therefore, the correct response is:
Option 2: An illustration shows a number line labeled Weight of Each Box in the Elevator. The number line ranges from 0 to 200 in 20 unit increments. A closed point is plotted at 0. A line extends from that point to the right, connecting with a closed point at 183.