Question

A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.

Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?

(1 point)
Responses

120p−22≥50
120 p minus 22 is greater than or equal to 50

120p−22>50
120 p minus 22 is greater than 50

120p−22<50
120p−22<50

120p−22≤50
120 p minus 22 is less than or equal to 50
Question 2
(1 point)
The class should sell each cookie forgreater than
less than
at most
at least
exactly

Answer 1

To determine the correct inequality for how much the class needs to sell the cookies for to reach their financial goal, let's break it down:

1. The total income from selling the cookies can be represented as \( 120p \), where \( p \) is the price per cookie.
2. The class incurs a cost of $22 for supplies.
3. They want to ensure that their profit (total income minus costs) is at least $50.

So we set up the inequality to reflect that:

\[
\text{Total Income} - \text{Costs} \geq \text{Desired Profit}
\]

Substituting the values:

\[
120p - 22 \geq 50
\]

Thus, the correct inequality to use is:

**120p − 22 ≥ 50**

---

For question 2 regarding how much the class should sell each cookie for:

To make sure their profit is at least $50, they need to sell each cookie for:

**at least** a certain price, which we will find by solving the inequality \( 120p - 22 \geq 50 \).

Solving the inequality:

1. Add 22 to both sides:

\[
120p \geq 50 + 22
\]
\[
120p \geq 72
\]

2. Divide by 120:

\[
p \geq \frac{72}{120}
\]
\[
p \geq 0.6
\]

So, the class should sell each cookie for **at least $0.60** in order to reach their financial goal.