Question

A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.

Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?

(1 point)
Responses

120p−22≤50
120 p minus 22 is less than or equal to 50

120p−22>50
120 p minus 22 is greater than 50

120p−22<50
120p−22<50

120p−22≥50
120 p minus 22 is greater than or equal to 50
Question 2
(1 point)
The class should sell each cookie for choose: greater than. at least. less than. exactly. at most. $0.60.

Answer 1

To determine the possible prices (p) the class can sell the cookies for in order to meet their goal of making at least $50, we need to set up the inequality.

The total revenue from selling the cookies can be calculated as \(120p\) (where \(p\) is the price per cookie). The total cost of supplies is $22. To make at least $50 profit, we set up the inequality as follows:

Total revenue - Total costs ≥ Desired profit
\[120p - 22 ≥ 50\]

So, the correct inequality is:
**120p - 22 ≥ 50**

For Question 2, we will need to solve for \(p\):

Starting from:
\[120p - 22 ≥ 50\]

Add 22 to both sides:
\[120p ≥ 72\]

Now, divide both sides by 120:
\[p ≥ \frac{72}{120}\]
\[p ≥ 0.60\]

Therefore, the class should sell each cookie for **at least** $0.60.

Final Responses:
1. 120p−22≥50
2. at least.