Asked by ant
what are the factor of the following trinomial?
3t^2 + 19t + 6
a) (t + 1)(3t + 6)
b) (3t + 1)(t + 6)
c) (t - 1) (3t + 6)
d) (3t - 1) (t + 6)
3t^2 + 19t + 6
a) (t + 1)(3t + 6)
b) (3t + 1)(t + 6)
c) (t - 1) (3t + 6)
d) (3t - 1) (t + 6)
Answers
Answered by
MathMate
If we note that 19=3*6+1*1, we would choose the answer where all signs are positive, and which gives the term 18t².
Answered by
Julia Brown
Look at answer (b).
Step 1.
Multiply 3t by t
Step 2.
Multiply 3t by 6
Step 3.
Multiply 1 by t
Step 4.
Multiply 1 by 6
That gives you
3t^2+18t+t+6
Step 5.
End Result
3t^2 + 19t + 6
Step 1.
Multiply 3t by t
Step 2.
Multiply 3t by 6
Step 3.
Multiply 1 by t
Step 4.
Multiply 1 by 6
That gives you
3t^2+18t+t+6
Step 5.
End Result
3t^2 + 19t + 6
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