To solve the inequality \( 3x + 5 \leq 14 \), we will isolate \( x \).
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Subtract 5 from both sides: \[ 3x + 5 - 5 \leq 14 - 5 \] which simplifies to: \[ 3x \leq 9 \]
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Next, divide both sides by 3: \[ \frac{3x}{3} \leq \frac{9}{3} \] which gives: \[ x \leq 3 \]
Now, we are looking for valid values of \( x \) that satisfy the inequality \( x \leq 3 \).
Among the provided responses:
- \( x = 3 \) is a solution since \( 3 \leq 3 \).
- \( x = 4 \) is not a solution since \( 4 > 3 \).
- \( x = 5 \) is not a solution since \( 5 > 3 \).
- \( x = 6 \) is not a solution since \( 6 > 3 \).
Therefore, the correct answer is: x = 3.