To analyze the function \( r = \sqrt[3]{\frac{3V}{\pi}} \), we can derive some key features from the formula.
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Understanding the Function:
- The formula expresses the relationship between the volume \( V \) of a cone and its radius \( r \).
- Since \( V \) is a volume, it is non-negative, meaning \( V \geq 0 \).
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Range of the Function:
- The formula indicates that \( r \) (the radius) is determined by the cube root of a non-negative number (since \( \frac{3V}{\pi} \geq 0 \) for \( V \geq 0 \)).
- Thus, \( r \) can be 0 or positive, meaning \( r \geq 0 \).
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Behavior of the Function:
- As \( V \) increases, \( r \) will also increase since the cube root function is an increasing function. This means if you increase \( V \), \( r \) will increase.
- However, the rate of increase of \( r \) will not be constant; it will increase at a decreasing rate due to the nature of the cube root function.
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Key Points:
- At \( V = 0 \), \( r = 0 \), indicating that if there is no volume, there is no radius.
- The function is not defined for negative volumes since volume cannot be negative in this context.
Given this analysis, the most accurate interpretation of the features of the function is:
The function is an increasing function, so the length of the radius of the cone is increasing at a decreasing rate.
This reflects that as the volume increases, the radius increases, but the rate of increase diminishes.