The correct response is:
The function is an increasing function, so as the height of the object increases, the time it takes the object to fall to the ground increases but not at a constant rate.
Explanation:
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The function \( t = h\sqrt{4} \) simplifies to \( t = 2h \), which is a linear function. The relationship between height \( h \) and time \( t \) is directly proportional, meaning as height increases, time increases linearly, rather than at an increasing rate.
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The statement about the minimum point at (0,0) is inaccurate because at zero height, the time to fall is zero, not 100 seconds.
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The domain of this function is \( h \geq 0 \) since height cannot be negative in this context, so the statement about the domain being \( h \leq 0 \) is incorrect.
Overall, the key features of the function indicate that while the time to fall increases as height increases, it does so at a constant rate due to the linear nature of the function.