Question
Mass (kg) Force (N)
5 25
10 50
15 75
20 100
Consider the data collected in science class. Different masses were thrown with varied amounts of force. The data table reflects Newton's 2nd Law of Motion, or F = ma. Based on the data collected, what conclusion can be stated about the objects acceleration?
Responses
A In all cases, the acceleration was the same.In all cases, the acceleration was the same.
B The acceleration decreased as the mass increased.The acceleration decreased as the mass increased.
C The acceleration increased as the force increased.The acceleration increased as the force increased.
D The greater the force, the greater the acceleration.
5 25
10 50
15 75
20 100
Consider the data collected in science class. Different masses were thrown with varied amounts of force. The data table reflects Newton's 2nd Law of Motion, or F = ma. Based on the data collected, what conclusion can be stated about the objects acceleration?
Responses
A In all cases, the acceleration was the same.In all cases, the acceleration was the same.
B The acceleration decreased as the mass increased.The acceleration decreased as the mass increased.
C The acceleration increased as the force increased.The acceleration increased as the force increased.
D The greater the force, the greater the acceleration.
Answers
Answer
u sure
Answered by
GPT-4o mini
To analyze the data and draw a conclusion about the objects' acceleration based on Newton's second law of motion (F = ma), we can calculate the acceleration for each set of data points using the formula:
\[ a = \frac{F}{m} \]
Let's calculate the acceleration for each data point:
1. For mass = 5 kg, force = 25 N:
\[ a = \frac{25 \, \text{N}}{5 \, \text{kg}} = 5 \, \text{m/s}^2 \]
2. For mass = 10 kg, force = 50 N:
\[ a = \frac{50 \, \text{N}}{10 \, \text{kg}} = 5 \, \text{m/s}^2 \]
3. For mass = 15 kg, force = 75 N:
\[ a = \frac{75 \, \text{N}}{15 \, \text{kg}} = 5 \, \text{m/s}^2 \]
4. For mass = 20 kg, force = 100 N:
\[ a = \frac{100 \, \text{N}}{20 \, \text{kg}} = 5 \, \text{m/s}^2 \]
From the calculations, we can see that the acceleration is constant at \(5 \, \text{m/s}^2\) for all different masses and forces.
Based on this analysis, the correct response is:
**A. In all cases, the acceleration was the same.**
\[ a = \frac{F}{m} \]
Let's calculate the acceleration for each data point:
1. For mass = 5 kg, force = 25 N:
\[ a = \frac{25 \, \text{N}}{5 \, \text{kg}} = 5 \, \text{m/s}^2 \]
2. For mass = 10 kg, force = 50 N:
\[ a = \frac{50 \, \text{N}}{10 \, \text{kg}} = 5 \, \text{m/s}^2 \]
3. For mass = 15 kg, force = 75 N:
\[ a = \frac{75 \, \text{N}}{15 \, \text{kg}} = 5 \, \text{m/s}^2 \]
4. For mass = 20 kg, force = 100 N:
\[ a = \frac{100 \, \text{N}}{20 \, \text{kg}} = 5 \, \text{m/s}^2 \]
From the calculations, we can see that the acceleration is constant at \(5 \, \text{m/s}^2\) for all different masses and forces.
Based on this analysis, the correct response is:
**A. In all cases, the acceleration was the same.**
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