To solve the quadratic equation \((x + 16)^{2} = 7\) using square roots, follow these steps:
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Move the constant to one side: \[ (x + 16)^{2} = 7 \]
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Take the square root of both sides: \[ x + 16 = \pm \sqrt{7} \]
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Isolate \(x\): \[ x = -16 \pm \sqrt{7} \]
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Calculate the two possible values for \(x\): \[ x_1 = -16 + \sqrt{7} \] \[ x_2 = -16 - \sqrt{7} \]
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Evaluate \(\sqrt{7} \approx 2.64575\): \[ x_1 = -16 + 2.64575 \approx -13.35425 \quad \text{(rounded to -13.35)} \] \[ x_2 = -16 - 2.64575 \approx -18.64575 \quad \text{(rounded to -18.65)} \]
So the two solutions to the equation \((x + 16)^{2} = 7\) are: \[ x \approx -13.35 \quad \text{and} \quad x \approx -18.65 \]
Final answers: \[ x_1 \approx -13.35, \quad x_2 \approx -18.65 \]