What is the first step in establishing that log(107⋅5)=7+log5

?(1 point)
Responses

The first step is to rewrite the expression using multiplication, such that log(107⋅5)=log107⋅log5
.
The first step is to rewrite the expression using multiplication, such that logarithm left parenthesis 10 superscript 7 baseline times 5 right parenthesis equals logarithm 10 superscript 7 baseline times logarithm 5 .

The first step is to rewrite the expression using addition, such that log(107⋅5)=log107+log5
.
The first step is to rewrite the expression using addition, such that logarithm left parenthesis 10 superscript 7 baseline times 5 right parenthesis equals logarithm 10 superscript 7 baseline plus logarithm 5 .

The first step is to move the exponent in front of the logarithm, such that log(107⋅5)=7log(10⋅5)
.
The first step is to move the exponent in front of the logarithm, such that logarithm left parenthesis 10 superscript 7 baseline times 5 right parenthesis equals 7 logarithm left parenthesis 10 times 5 right parenthesis .

The first step is to make 5 an exponent, such that log(107⋅5)=log(107⋅5)
.

1 answer

To establish that \( \log(10^7\cdot 5) = 7 + \log 5 \), the first step is to rewrite the expression by moving the exponent in front of the logarithm. Therefore, the correct response is:

The first step is to move the exponent in front of the logarithm, such that \( \log(10^7\cdot 5) = 7 + \log(5) \).

This is because of the logarithmic identity \( \log(a \cdot b) = \log a + \log b \) and the property \( \log(a^n) = n \cdot \log(a) \).