Asked by pup
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A cone shows a radius of 6 and hypotenuse or side as 11.
What is the surface area of the cone? Use 3.14 for pi and round to the nearest tenth, if necessary.
(1 point)
its not 173.3
A cone shows a radius of 6 and hypotenuse or side as 11.
What is the surface area of the cone? Use 3.14 for pi and round to the nearest tenth, if necessary.
(1 point)
its not 173.3
Answers
Answered by
pup
that is ... right!!!
Answered by
GPT-4o mini
To find the surface area of a cone, we can use the following formula:
\[
\text{Surface Area} = \pi r (r + l)
\]
where \( r \) is the radius and \( l \) is the slant height (hypotenuse).
From the information provided:
- The radius \( r = 6 \)
- The slant height \( l = 11 \)
Now substitute these values into the formula:
\[
\text{Surface Area} = \pi \times 6 \times (6 + 11)
\]
\[
= \pi \times 6 \times 17
\]
\[
= \pi \times 102
\]
Now substitute \( \pi \) with \( 3.14 \):
\[
\text{Surface Area} = 3.14 \times 102
\]
\[
= 320.28
\]
Rounding to the nearest tenth:
\[
\text{Surface Area} \approx 320.3
\]
Thus, the surface area of the cone is approximately **320.3 square units**.
\[
\text{Surface Area} = \pi r (r + l)
\]
where \( r \) is the radius and \( l \) is the slant height (hypotenuse).
From the information provided:
- The radius \( r = 6 \)
- The slant height \( l = 11 \)
Now substitute these values into the formula:
\[
\text{Surface Area} = \pi \times 6 \times (6 + 11)
\]
\[
= \pi \times 6 \times 17
\]
\[
= \pi \times 102
\]
Now substitute \( \pi \) with \( 3.14 \):
\[
\text{Surface Area} = 3.14 \times 102
\]
\[
= 320.28
\]
Rounding to the nearest tenth:
\[
\text{Surface Area} \approx 320.3
\]
Thus, the surface area of the cone is approximately **320.3 square units**.
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