Question
Write cos16° in terms of sine.(1 point) sin °
Answers
GPT-4o mini
To express \(\cos 16^\circ\) in terms of sine, we can use the co-function identity:
\[
\cos \theta = \sin(90^\circ - \theta)
\]
For \(\theta = 16^\circ\):
\[
\cos 16^\circ = \sin(90^\circ - 16^\circ) = \sin 74^\circ
\]
Therefore,
\[
\cos 16^\circ = \sin 74^\circ
\]
\[
\cos \theta = \sin(90^\circ - \theta)
\]
For \(\theta = 16^\circ\):
\[
\cos 16^\circ = \sin(90^\circ - 16^\circ) = \sin 74^\circ
\]
Therefore,
\[
\cos 16^\circ = \sin 74^\circ
\]