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Original Question
Find the distance between (2, 3) and (-4, - 9). Round your answer to the nearest hundredth, if necessary.Asked by Royal cheesecake
Find the distance between (−8, −3) and (−2, −5) . Round your answer to the nearest hundredth, if necessary.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between the points \((-8, -3)\) and \((-2, -5)\), you can use the distance formula, which is given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-8, -3)\) and \((x_2, y_2) = (-2, -5)\).
Plugging in the coordinates:
\[
d = \sqrt{((-2) - (-8))^2 + ((-5) - (-3))^2}
\]
Calculating the differences:
\[
x_2 - x_1 = -2 + 8 = 6
\]
\[
y_2 - y_1 = -5 + 3 = -2
\]
Now squaring those differences:
\[
d = \sqrt{(6)^2 + (-2)^2} = \sqrt{36 + 4} = \sqrt{40}
\]
Now we simplify \(\sqrt{40}\):
\[
\sqrt{40} = \sqrt{4 \times 10} = 2\sqrt{10}
\]
Next, we can calculate the numeric value of \(2\sqrt{10}\):
\[
\sqrt{10} \approx 3.1623 \quad \text{(approx)}
\]
\[
2\sqrt{10} \approx 2 \times 3.1623 \approx 6.3246
\]
Now rounding to the nearest hundredth:
\[
d \approx 6.32
\]
Thus, the distance between the points \((-8, -3)\) and \((-2, -5)\) is approximately \(\boxed{6.32}\).
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-8, -3)\) and \((x_2, y_2) = (-2, -5)\).
Plugging in the coordinates:
\[
d = \sqrt{((-2) - (-8))^2 + ((-5) - (-3))^2}
\]
Calculating the differences:
\[
x_2 - x_1 = -2 + 8 = 6
\]
\[
y_2 - y_1 = -5 + 3 = -2
\]
Now squaring those differences:
\[
d = \sqrt{(6)^2 + (-2)^2} = \sqrt{36 + 4} = \sqrt{40}
\]
Now we simplify \(\sqrt{40}\):
\[
\sqrt{40} = \sqrt{4 \times 10} = 2\sqrt{10}
\]
Next, we can calculate the numeric value of \(2\sqrt{10}\):
\[
\sqrt{10} \approx 3.1623 \quad \text{(approx)}
\]
\[
2\sqrt{10} \approx 2 \times 3.1623 \approx 6.3246
\]
Now rounding to the nearest hundredth:
\[
d \approx 6.32
\]
Thus, the distance between the points \((-8, -3)\) and \((-2, -5)\) is approximately \(\boxed{6.32}\).
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