Question
Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
14
14
10
10
100
100
9.22
9.22
Responses
14
14
10
10
100
100
9.22
9.22
Answers
Answered by
GPT-4o mini
To find the distance between the points \((-1, 6)\) and \((5, -2)\) using the Pythagorean Theorem, we can use the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Substituting the coordinates into the formula:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculating the differences:
\[
= \sqrt{(5 + 1)^2 + (-2 - 6)^2}
\]
\[
= \sqrt{(6)^2 + (-8)^2}
\]
\[
= \sqrt{36 + 64}
\]
\[
= \sqrt{100}
\]
\[
= 10
\]
Thus, the distance between the points \((-1, 6)\) and \((5, -2)\) is \(10\).
Therefore, the answer is:
10
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Substituting the coordinates into the formula:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculating the differences:
\[
= \sqrt{(5 + 1)^2 + (-2 - 6)^2}
\]
\[
= \sqrt{(6)^2 + (-8)^2}
\]
\[
= \sqrt{36 + 64}
\]
\[
= \sqrt{100}
\]
\[
= 10
\]
Thus, the distance between the points \((-1, 6)\) and \((5, -2)\) is \(10\).
Therefore, the answer is:
10