Jerrica is packing a box that can hold at most 65 pounds. She starts by putting a container in the box that weighs 26 pounds. She plans to fill the rest of the box with books. Each book she places in the box weighs 1.3 pounds. Write an inequality for the number of books Jerrica can put in the box, and describe the solutions.(2 points) $$x+ $$ ≤ $$, where x is the number of books Jerrica can put in the box. Jerrica can put at most $$ books in the box.

Question

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Answer 1

To set up the inequality, we need to consider the weight of the container and the books Jerrica can add.

1. The box can hold a maximum of 65 pounds.
2. The weight of the container is 26 pounds.
3. Each book weighs 1.3 pounds, and Jerrica will let \( x \) represent the number of books.

Now we can write the inequality representing the total weight in the box:

\[ 26 + 1.3x \leq 65 \]

Next, we'll solve for \( x \):

1. Subtract 26 from both sides: \[ 1.3x \leq 65 - 26 \] \[ 1.3x \leq 39 \]

2. Divide both sides by 1.3: \[ x \leq \frac{39}{1.3} \] \[ x \leq 30 \]

So the inequality is: \[ x \leq 30 \]

Solutions:

The solutions to this inequality indicate that Jerrica can put at most 30 books in the box. Thus, \( x \) can take any whole number value from 0 to 30, inclusive.

In conclusion, Jerrica can put at most 30 books in the box.

Answer 2

wrong