To express \((x - 8)^2\) as a trinomial in standard form, we need to expand the expression.
Using the formula for the square of a binomial, \((a - b)^2 = a^2 - 2ab + b^2\):
- Here, \(a = x\) and \(b = 8\).
- Calculate \(a^2\): \[ x^2 \]
- Calculate \(-2ab\): \[ -2(x)(8) = -16x \]
- Calculate \(b^2\): \[ 8^2 = 64 \]
Now combine all the parts together: \[ (x - 8)^2 = x^2 - 16x + 64 \]
Therefore, the trinomial in standard form is: \[ \boxed{x^2 - 16x + 64} \]
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