Question

balance the below equations by adding appropriate coefficients
a. Ca(OH)2+Al2(SO4)3~CaSO4+Al(OH)3

Answer 1

To balance the equation \( \text{Ca(OH)}_2 + \text{Al}_2(\text{SO}_4)_3 \rightarrow \text{CaSO}_4 + \text{Al(OH)}_3 \), we'll follow the steps for balancing chemical equations.

1. Write down the unbalanced equation:
\[
\text{Ca(OH)}_2 + \text{Al}_2(\text{SO}_4)_3 \rightarrow \text{CaSO}_4 + \text{Al(OH)}_3
\]

2. Count the number of each atom on both sides of the equation:
- Reactants:
- Ca: 1
- O: 2 (from Ca(OH)₂) + 12 (from Al₂(SO₄)₃) = 14
- H: 2
- Al: 2
- S: 3
- Products:
- Ca: 1
- O: 4 (from CaSO₄) + 3 (from Al(OH)₃) = 7
- H: 3
- Al: 1
- S: 1

3. Start balancing the more complex molecules first:
- Balance Al: There are 2 Al on the left, so we need 2 Al(OH)₃ on the right:
\[
\text{Ca(OH)}_2 + \text{Al}_2(\text{SO}_4)_3 \rightarrow \text{CaSO}_4 + 2 \text{Al(OH)}_3
\]

4. Count again:
- Reactants:
- Ca: 1
- O: 2 (from Ca(OH)₂) + 12 = 14
- H: 2
- Al: 2
- S: 3
- Products:
- Ca: 1
- O: 4 (from CaSO₄) + 6 (from 2Al(OH)₃) = 10
- H: 6
- Al: 2
- S: 1

5. Balance sulfur (S): Since there are 3 SO₄ on the left, we need 3 CaSO₄ on the right:
\[
3 \text{Ca(OH)}_2 + \text{Al}_2(\text{SO}_4)_3 \rightarrow 3\text{CaSO}_4 + 2 \text{Al(OH)}_3
\]

6. Count again:
- Reactants:
- Ca: 3
- O: 6 + 12 = 18
- H: 6
- Al: 2
- S: 3
- Products:
- Ca: 3
- O: 12 + 6 = 18
- H: 6
- Al: 2
- S: 3

Now everything is balanced correctly.

The balanced equation is:
\[
3 \text{Ca(OH)}_2 + \text{Al}_2(\text{SO}_4)_3 \rightarrow 3 \text{CaSO}_4 + 2 \text{Al(OH)}_3
\]