Question

balance the below equations by adding appropriate coefficients
a. PbBr2+HCl~HBr+PbCl2

Answer 1

To balance the equation \( \text{PbBr}_2 + \text{HCl} \rightarrow \text{HBr} + \text{PbCl}_2 \), we need to ensure that the number of each type of atom is the same on both sides of the equation.

1. **Count the atoms on each side:**
- Reactants:
- \( \text{Pb} = 1 \)
- \( \text{Br} = 2 \)
- \( \text{Cl} = 1 \)
- \( \text{H} = 1 \)

- Products:
- \( \text{Pb} = 1 \)
- \( \text{Br} = 1 \)
- \( \text{Cl} = 2 \)
- \( \text{H} = 1 \)

2. **Balance the bromine and chlorine:**
- To balance the bromine, we need 2 HBr on the products side:
- Updating the products: \( 2 \text{HBr} \)
- Now count the atoms:
- Products:
- \( \text{Br} = 2 \) (2 HBr)
- \( \text{Cl} = 2 \) (since we have the same \( \text{PbCl}_2 \))
- \( \text{H} = 2 \) (because now we have 2 HBr)

3. **Update the reactants:**
- This means we need 2 HCl in the reactants side to balance the chlorine and hydrogen:

Now the balanced equation looks like this:

\[
\text{PbBr}_2 + 2 \text{HCl} \rightarrow 2 \text{HBr} + \text{PbCl}_2
\]

Thus, the full balanced equation is:

\[
\text{PbBr}_2 + 2 \text{HCl} \rightarrow 2 \text{HBr} + \text{PbCl}_2
\]