To find the ordered pairs for the function \( y = 5(14)^x \) with the given x-values of -2, -1, 0, and 1, we will substitute each x-value into the function and calculate the corresponding y-value.
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For \( x = -2 \): \[ y = 5(14)^{-2} = 5 \times \frac{1}{14^2} = 5 \times \frac{1}{196} = \frac{5}{196} \approx 0.0255 \]
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For \( x = -1 \): \[ y = 5(14)^{-1} = 5 \times \frac{1}{14} \approx \frac{5}{14} \approx 0.3571 \]
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For \( x = 0 \): \[ y = 5(14)^0 = 5 \times 1 = 5 \]
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For \( x = 1 \): \[ y = 5(14)^1 = 5 \times 14 = 70 \]
Now we summarize the ordered pairs:
- For \( x = -2 \): \( y \approx 0.0255 \) so the pair is \( (-2, 0.0255) \)
- For \( x = -1 \): \( y \approx 0.3571 \) so the pair is \( (-1, 0.3571) \)
- For \( x = 0 \): \( y = 5 \) so the pair is \( (0, 5) \)
- For \( x = 1 \): \( y = 70 \) so the pair is \( (1, 70) \)
Thus, the correct ordered pairs for the given x-values of -2, -1, 0, and 1 are approximately:
\( (-2, 0.0255), (-1, 0.3571), (0, 5), (1, 70) \)
You should compare these results with the options you have, but it seems none of the provided options match these calculated values. Make sure there isn't a typo in the function, as the calculations follow standard exponent rules.
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