Question

balance the below equations by adding appropriate coefficients
a. P4+Br2~PBr3

Answer 1

To balance the equation \( \text{P}_4 + \text{Br}_2 \rightarrow \text{PBr}_3 \), we can follow these steps:

1. **Identify the number of each type of atom on both sides of the equation.**
- On the left side, there are 4 phosphorus (P) atoms in \( \text{P}_4 \) and 2 bromine (Br) atoms in \( \text{Br}_2 \).
- On the right side, there is 1 phosphorus atom and 3 bromine atoms in \( \text{PBr}_3 \).

2. **Set up coefficients to balance the atoms:**
- To balance phosphorus, you need 4 PBr\(_3\) on the right side:
- This gives you \( 4 \text{P} \) on the right side (from \( 4 \text{PBr}_3 \)).

- You can then write the equation as:
\[
\text{P}_4 + \text{Br}_2 \rightarrow 4 \text{PBr}_3
\]

3. **Now balance bromine:**
- In \( 4 \text{PBr}_3 \), there are \( 4 \times 3 = 12 \) Br atoms needed.
- On the left side, you would need \( 6 \text{Br}_2 \) to provide 12 Br atoms.

4. **Now the balanced equation looks like this:**
\[
\text{P}_4 + 6 \text{Br}_2 \rightarrow 4 \text{PBr}_3
\]

So the final balanced equation is:
\[
\text{P}_4 + 6 \text{Br}_2 \rightarrow 4 \text{PBr}_3
\]