Question

balance the below equations by adding appropriate coefficients
a. AlBr3+K~KBr+ Al

Answer 1

To balance the equation \( \text{AlBr}_3 + \text{K} \rightarrow \text{KBr} + \text{Al} \), we first write down the unbalanced equation:

\[
\text{AlBr}_3 + \text{K} \rightarrow \text{KBr} + \text{Al}
\]

Now, we need to balance the number of each type of atom on both sides of the equation.

1. **Aluminum (Al)**: There is 1 Al in AlBr3 and 1 Al in the products (on the right side).
2. **Bromine (Br)**: There are 3 Br atoms in AlBr3 and only 1 Br atom in KBr. Therefore, we will need 3 KBr on the product side to balance bromine.
3. **Potassium (K)**: If we add 3 KBr, we will need 3 K on the reactant side to balance the potassium since each KBr has 1 K.

Thus, the balanced equation becomes:

\[
\text{AlBr}_3 + 3\text{K} \rightarrow 3\text{KBr} + \text{Al}
\]

So the final balanced equation with coefficients is:

\[
1 \text{AlBr}_3 + 3 \text{K} \rightarrow 3 \text{KBr} + 1 \text{Al}
\]