Asked by woosan♥
Apply the Pythagorean Theorem to find the length between (−1, 6)
and (5, −2)
. Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
9.22
9.22
10
10
100
100
14
and (5, −2)
. Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
9.22
9.22
10
10
100
100
14
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between the points \((-1, 6)\) and \( (5, -2)\), we can use the distance formula, which is derived from the Pythagorean Theorem. The distance \(d\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Now plug in the values:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculate \(x_2 - x_1\) and \(y_2 - y_1\):
\[
x_2 - x_1 = 5 + 1 = 6
\]
\[
y_2 - y_1 = -2 - 6 = -8
\]
Now substitute these into the distance formula:
\[
d = \sqrt{(6)^2 + (-8)^2}
\]
Calculate the squares:
\[
d = \sqrt{36 + 64}
\]
\[
d = \sqrt{100}
\]
Now find the square root:
\[
d = 10
\]
Thus, the length between the points \((-1, 6)\) and \( (5, -2)\) is \(10\).
Rounded to the nearest hundredth, the answer remains:
**10**
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Now plug in the values:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculate \(x_2 - x_1\) and \(y_2 - y_1\):
\[
x_2 - x_1 = 5 + 1 = 6
\]
\[
y_2 - y_1 = -2 - 6 = -8
\]
Now substitute these into the distance formula:
\[
d = \sqrt{(6)^2 + (-8)^2}
\]
Calculate the squares:
\[
d = \sqrt{36 + 64}
\]
\[
d = \sqrt{100}
\]
Now find the square root:
\[
d = 10
\]
Thus, the length between the points \((-1, 6)\) and \( (5, -2)\) is \(10\).
Rounded to the nearest hundredth, the answer remains:
**10**
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