Jerrica is packing a box that can hold at most 65 pounds. She starts by putting a container in the box that weighs 26 pounds. She plans to fill the rest of the box with books. Each book she places in the box weighs 1.3 pounds. Write an inequality for the number of books Jerrica can put in the box, and describe the solutions.(2 points)

Question

blank x+ blank ≤ blank
, where x
is the number of books Jerrica can put in the box. Jerrica can put at most
books in the box.

1i have 4 blanks to fill out

Answer 1

To solve the problem, we need to set up an inequality based on the given weight limits.

1. Jerrica's box can hold at most 65 pounds.
2. She puts a container that weighs 26 pounds in the box.
3. Each book weighs 1.3 pounds, and we need to find out how many books (x) she can add without exceeding the weight limit.

The inequality can be written as:

\[ 26 + 1.3x \leq 65 \]

Now we can fill in the blanks for the inequality \(x + \text{blank} \leq \text{blank}\):

• First blank (coefficient of x): 1.3
• Second blank (constant term): 26
• Third blank (right side): 65

Complete inequality:

\[ 1.3x + 26 \leq 65 \]

Now, to describe the solutions.

We can solve for \(x\):

1. Subtract 26 from both sides: \[ 1.3x \leq 65 - 26 \] \[ 1.3x \leq 39 \]

2. Divide both sides by 1.3: \[ x \leq \frac{39}{1.3} \] \[ x \leq 30 \]

This means Jerrica can put at most 30 books in the box.

Final Answer: \[ \text{Inequality: } 1.3x + 26 \leq 65 \] Jerrica can put at most 30 books in the box.