The value of x in log2x=1

is which of the following?(1 point)
Responses

0
0

−2
negative 2

1
1

2

1 answer

To solve the equation \( \log_2 x = 1 \), we can rewrite it in exponential form.

The equation \( \log_2 x = 1 \) means that \( x \) is equal to \( 2 \) raised to the power of \( 1 \):

\[ x = 2^1 \]

Thus,

\[ x = 2 \]

So, the value of \( x \) is \( \mathbf{2} \).

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