To analyze the given function \( h(x) = 49(27)^x \), we note that:
- \( 49 \) is a positive constant.
- The base \( 27 \) is also positive and greater than 1, indicating that the exponential function will increase as \( x \) increases.
Since \( (27)^x \) is always greater than 0 for any real number \( x \), it follows that \( h(x) \) is also positive for all \( x \):
\[ h(x) = 49(27)^x > 0 \]
Thus, the function does not touch or cross the x-axis, meaning there's no \( x \) for which \( h(x) \) is zero.
The range of the function can therefore be described by the inequality:
\[ y > 0 \]
So the correct response is:
y > 0