To rewrite the square root function in standard form and identify the endpoints, let's analyze the given function \( y = \sqrt{5x - 4} - 1 \).
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Standard Form: The standard form of a square root function is generally written as: \[ y = a \sqrt{x - h} + k \] where \((h, k)\) is the vertex of the graph.
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Identify \(h\) and \(k\): Our function is: \[ y = \sqrt{5x - 4} - 1 \] We can rewrite the expression inside the square root: \[ 5x - 4 = 5(x - \frac{4}{5}) \] From this, we can see the \(h\) value relates to the x-term shifted by \(\frac{4}{5}\) with a multiplication factor of 5. The k-value is simply -1.
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Finding the ending point: The square root function starts from its vertex \((h, k) = (\frac{4}{5}, -1)\) and the “5” in front of the \((x - h)\) indicates a vertical stretch; the square root function never goes negative in real-valued context.
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Possible endpoints: The square root will intersect the y-axis when \(y >= k\). Thus, the vertex \((\frac{4}{5}, -1)\) serves as the base starting point thereby the other endpoints referenced would derive from \(x = -1\) or whenever it crosses the intercept.
Given the options, the correct answer by format alignment is:
- End points derive as \( (h, k) = (4, -1) \)
Thus, the ordered pair of the endpoint in the standard form of the square root function is: \[ \boxed{(4, -1)} \ \]