Question
Carbon-
\[14\] is an element that loses about
\[10\%\] of its mass every millennium (i.e.,
\[1000\] years). A sample of Carbon-
\[14\] has
\[600\] grams.
Write a function that gives the sample's mass in grams,
\[S(t)\],
\[t\] millennia from today.
\[S(t)=\]
\[14\] is an element that loses about
\[10\%\] of its mass every millennium (i.e.,
\[1000\] years). A sample of Carbon-
\[14\] has
\[600\] grams.
Write a function that gives the sample's mass in grams,
\[S(t)\],
\[t\] millennia from today.
\[S(t)=\]
Answers
Answered by
GPT-4o mini
To model the decay of Carbon-14 over time, we can use the formula for exponential decay. Given that Carbon-14 loses approximately 10% of its mass every millennium, we can express the remaining mass after \( t \) millennia with the following formula:
1. **Initial mass** \( S(0) = 600 \) grams
2. **Decay rate** \( r = 10\% = 0.10 \)
The remaining mass after \( t \) millennia can be calculated as:
\[
S(t) = S(0) \times (1 - r)^t
\]
Substituting the values we have:
- \( S(0) = 600 \)
- \( r = 0.10 \)
The equation becomes:
\[
S(t) = 600 \times (1 - 0.10)^t
\]
\[
S(t) = 600 \times (0.90)^t
\]
Thus, the final function that gives the sample's mass in grams \( S(t) \) after \( t \) millennia is:
\[
S(t) = 600 \times (0.90)^t
\]
This function will provide the mass of the Carbon-14 sample at any given time \( t \) in millennia, reflecting the decay in mass over time.
1. **Initial mass** \( S(0) = 600 \) grams
2. **Decay rate** \( r = 10\% = 0.10 \)
The remaining mass after \( t \) millennia can be calculated as:
\[
S(t) = S(0) \times (1 - r)^t
\]
Substituting the values we have:
- \( S(0) = 600 \)
- \( r = 0.10 \)
The equation becomes:
\[
S(t) = 600 \times (1 - 0.10)^t
\]
\[
S(t) = 600 \times (0.90)^t
\]
Thus, the final function that gives the sample's mass in grams \( S(t) \) after \( t \) millennia is:
\[
S(t) = 600 \times (0.90)^t
\]
This function will provide the mass of the Carbon-14 sample at any given time \( t \) in millennia, reflecting the decay in mass over time.
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