Question
Busby is a famous cat on a video-sharing app. The total number of likes for Busby's most popular video grows by 10% every month. The total number of likes for the video in m months from now will be 4000×1.1
m
. How many likes does Busby's video have right now?
m
. How many likes does Busby's video have right now?
Answers
Answer
how many likes did busby have one month ago
Answered by
GPT-4o mini
To determine the current number of likes for Busby's video, we need to understand how the likes grow over time.
We know that the likes for the video in \( m \) months from now is given by:
\[
\text{Likes in } m \text{ months} = 4000 \times 1.1^m
\]
Since the likes grow by 10% each month, we can express the current number of likes (let's call it \( L_0 \)) using the formula for compound growth. The relationship can be expressed as:
\[
L(m) = L_0 \times (1.1)^m
\]
where:
- \( L(m) \) is the number of likes after \( m \) months,
- \( L_0 \) is the current number of likes,
- \( 1.1^m \) is the growth factor over \( m \) months.
According to the given information:
\[
4000 \times 1.1^m = L_0 \times 1.1^m
\]
We can see that both sides have \( 1.1^m \). Assuming \( 1.1^m \) is not equal to zero, we can divide both sides by \( 1.1^m \):
\[
4000 = L_0
\]
Thus, the current number of likes for Busby's video is:
\[
\boxed{4000}
\]
We know that the likes for the video in \( m \) months from now is given by:
\[
\text{Likes in } m \text{ months} = 4000 \times 1.1^m
\]
Since the likes grow by 10% each month, we can express the current number of likes (let's call it \( L_0 \)) using the formula for compound growth. The relationship can be expressed as:
\[
L(m) = L_0 \times (1.1)^m
\]
where:
- \( L(m) \) is the number of likes after \( m \) months,
- \( L_0 \) is the current number of likes,
- \( 1.1^m \) is the growth factor over \( m \) months.
According to the given information:
\[
4000 \times 1.1^m = L_0 \times 1.1^m
\]
We can see that both sides have \( 1.1^m \). Assuming \( 1.1^m \) is not equal to zero, we can divide both sides by \( 1.1^m \):
\[
4000 = L_0
\]
Thus, the current number of likes for Busby's video is:
\[
\boxed{4000}
\]
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