Question
Jazmin built a model car. Her model is 9 inches long. The actual car that her model represents is 15 feet long.
Jazmin wrote a ratio comparing the length of the model to the length of the actual car and then converted that rate to a unit rate.
What was the rate?
Responses
9 in.15 ft
9 in. over 15 ft
15 ft9 in.
Jazmin wrote a ratio comparing the length of the model to the length of the actual car and then converted that rate to a unit rate.
What was the rate?
Responses
9 in.15 ft
9 in. over 15 ft
15 ft9 in.
Answers
Answered by
GPT-4o mini
To find the rate comparing the length of the model to the length of the actual car, we need to express it in terms of one unit. Jazmin's model car is 9 inches long, and the actual car is 15 feet long.
First, we can convert 15 feet into inches, since there are 12 inches in a foot:
\[
15 \text{ ft} \times 12 \text{ in/ft} = 180 \text{ in}
\]
Now, we can write the ratio of the model's length to the actual car's length:
\[
\text{Ratio} = \frac{9 \text{ in}}{180 \text{ in}}
\]
Now, let's simplify this ratio:
\[
\frac{9}{180} = \frac{1}{20}
\]
Thus, the unit rate comparing the length of the model to the length of the actual car can be expressed as:
\[
\frac{1 \text{ in}}{20 \text{ in}}
\]
So, the rate Jazmin expressed is \( \frac{9 \text{ in}}{15 \text{ ft}} \) or \( 9 \text{ in} \, \text{over} \, 15 \text{ ft} \) before converting it to unit rate.
The answer is:
**9 in. over 15 ft**.
First, we can convert 15 feet into inches, since there are 12 inches in a foot:
\[
15 \text{ ft} \times 12 \text{ in/ft} = 180 \text{ in}
\]
Now, we can write the ratio of the model's length to the actual car's length:
\[
\text{Ratio} = \frac{9 \text{ in}}{180 \text{ in}}
\]
Now, let's simplify this ratio:
\[
\frac{9}{180} = \frac{1}{20}
\]
Thus, the unit rate comparing the length of the model to the length of the actual car can be expressed as:
\[
\frac{1 \text{ in}}{20 \text{ in}}
\]
So, the rate Jazmin expressed is \( \frac{9 \text{ in}}{15 \text{ ft}} \) or \( 9 \text{ in} \, \text{over} \, 15 \text{ ft} \) before converting it to unit rate.
The answer is:
**9 in. over 15 ft**.
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