Asked by Vince
How would I make z the subject of the formulae:
x=y(z-y)/z
x=y(z-y)/z
Answers
Answered by
drwls
(z-y)/z = 1 - (y/z) = x/y
y/z = 1 - (x/y)= (y-x)/y
z/y = y/(y-x)
z = y^2/(y-x)
y/z = 1 - (x/y)= (y-x)/y
z/y = y/(y-x)
z = y^2/(y-x)
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