Question

For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
Responses

6(x − 8) = 48
6 left parenthesis x minus 8 right parenthesis equals 48

6x − 8 = 48
6 x minus 8 equals 48

6(x + 8) = 48
6 left parenthesis x plus 8 right parenthesis equals 48

8(x − 6) = 48

Answer 1

To identify which equation requires the steps of dividing both sides by 6 first and then adding 8 to both sides, we can analyze each equation.

1. For **6(x − 8) = 48**:
- If we divide both sides by 6: \( x - 8 = 8 \); then adding 8 gives \( x = 16 \).

2. For **6x − 8 = 48**:
- If we add 8 to both sides first: \( 6x = 56 \); then dividing by 6 gives \( x = \frac{56}{6} \).

3. For **6(x + 8) = 48**:
- If we divide by 6 first: \( x + 8 = 8 \); then subtracting 8 gives \( x = 0 \).

4. For **8(x − 6) = 48**:
- If we divide by 8 first: \( x - 6 = 6 \); then adding 6 gives \( x = 12 \).

Based on the analysis, only the first equation, **6(x - 8) = 48**, allows for the division by 6 first and then the addition of 8 to solve for x directly.

So, the answer is:
**6(x - 8) = 48**