Question

Hey you didnt laugh at my joke

Answer 1

Got a big mouthful today lol What is the first step in establishing that log(107⋅5)=7+log5 ? Responses The first step is to rewrite the expression using multiplication, such that log(107⋅5)=log107⋅log5 . The first step is to rewrite the expression using multiplication, such that the log of open paren 10 to the 7th power times 5 close paren is equal to log times 10 to the 7th power times log 5. - no response given The first step is to rewrite the expression using addition, such that log(107⋅5)=log107+log5 . The first step is to rewrite the expression using addition, such that the log of open paren 10 to the 7th power times 5 close paren is equal to the log of 10 to the 7th power plus log 5. - correct The first step is to make 5 an exponent, such that log(107⋅5)=log(107⋅5) . The first step is to make 5 an exponent, such that the log of open paren 10 to the 7th power times 5 close paren is equal to the log of open paren 10 raised to the 7 times 5 power close paren. - no response given The first step is to move the exponent in front of the logarithm, such that log(107⋅5)=7log(10⋅5) .

Answer 2

I’m sorry about that! What was your joke? I’d love to hear it!