To find the equivalence between the two expressions provided, let's analyze them step by step.
Given Expressions:
Expression 1:
\( k + k + 1 + 1 - 1 \)
Expression 2:
\( k + k + 1 \)
Simplifying Expression 1:
- Combine like terms:
- Add the \( k \) terms: \( k + k = 2k \)
- Add the constant terms: \( 1 + 1 - 1 = 1 \)
- Therefore, after simplification:
- Expression 1: \( 2k + 1 \)
Simplifying Expression 2:
- Combine like terms:
- Add the \( k \) terms: \( k + k = 2k \)
- The remaining constant is \( 1 \).
- Therefore, after simplification:
- Expression 2: \( 2k + 1 \)
Equivalence Check:
Now we have:
- Simplified Expression 1: \( 2k + 1 \)
- Simplified Expression 2: \( 2k + 1 \)
They are equivalent: \( 2k + 1 = 2k + 1 \)
Filling in the Blanks:
Going back to your statement about filling in the blanks for:
Expression 1: \( 2k + \text{blank} - 1 \)
Expression 2: \( 2k + \text{blank} \)
Since both simplified expressions yield \( 2k + 1 \), we can determine:
- For Expression 1: The blank must be \( 2 \) because \( 2k + 2 - 1 = 2k + 1 \).
- For Expression 2: The blank must also be \( 1 \) because it needs to match \( 2k + 1 \).
Final Answer:
- Expression 1: \( 2k + 2 - 1 \)
- Expression 2: \( 2k + 1 \)
Since it was stated that Expression 1 is not 1 or 2, the blank in Expression 1 should be specifically 2 in this context.