Letter tiles H, O, N, E, S, T are shuffled and placed in a box. A letter is selected at random. What is the probability of selecting letter A ?

Question

6/0
0
1/6
1

Answer 1

To determine the probability of selecting the letter "A" from the box containing the letters H, O, N, E, S, and T, we first note that the total number of letters present is 6.

The letter "A" is not among the letters in the box (the letters are H, O, N, E, S, and T). Therefore, the number of favorable outcomes for selecting "A" is 0.

The probability \( P \) of an event is given by the formula:

\[ P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

In this case, we have:

• Number of favorable outcomes = 0 (since "A" is not in the box)
• Total number of outcomes = 6 (the letters H, O, N, E, S, T)

So,

\[ P(A) = \frac{0}{6} = 0 \]

Thus, the probability of selecting the letter "A" is 0. The correct answer is: 0.