Question
Question 1 A)A class __ lever never has a mechanical advantage. A class __ lever always has a mechanical advantage. A class __ lever could go either way.(1 point) Responses 2; 3; 1 2; 3; 1 3; 2; 1 3; 2; 1 1; 2; 3 1; 2; 3 2; 1; 3 2; 1; 3 Question 2 A)A lever is used to lift an object with a weight of 60 Newtons. The effort force is 15 meters from the fulcrum, while the load force is 5 meters from the fulcrum. What is the mechanical advantage?(1 point) Responses 12 12 3 3 4 4 75 75 Question 3 A)With which class of levers is it possible to increase the force that must be applied?(1 point) Responses Class 3 and 4 Class 3 and 4 Class 2 and 3 Class 2 and 3 Class 1 and 3 Class 1 and 3 Class 1 and 2 Class 1 and 2 Question 4 A)600 Joules of work is used to lift a box from the ground to a height of six meters. How much work would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters?(1 point) Responses 600 J 600 J 100 J 100 J 50 J 50 J 72 J 72 J Question 5 A)A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?(1 point) Responses 100 N 100 N 1600 N 1600 N 800 N 800 N 4000 N 4000 N
Answers
Answer
there is no 400 there is 4000,800,100, or 1600
Answered by
GPT-4o mini
Here are the answers for each of the questions:
**Question 1**: The correct response is **2; 1; 3**.
- A class 1 lever can have any mechanical advantage depending on the position of the fulcrum.
- A class 2 lever always has a mechanical advantage.
- A class 3 lever never has a mechanical advantage.
**Question 2**: The mechanical advantage (MA) can be calculated using the formula:
\[ \text{MA} = \frac{\text{Distance from Effort to Fulcrum}}{\text{Distance from Load to Fulcrum}} = \frac{15 \text{ m}}{5 \text{ m}} = 3 \]
The correct response is **3**.
**Question 3**: The class of levers that can increase the force applied is **Class 2 and 3**.
The correct response is **Class 2 and 3**.
**Question 4**: The work done by the lever can be calculated using the same formula since the height is the same (600 Joules is equivalent to that system). The work done remains the same since it's just leveraging methods.
The correct response is **600 J**.
**Question 5**: To find the force applied, we can use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
We need to calculate the distance the effort arm moves to lift the load. The distance moved by the load is 4 m. The load arm is 2 m, thus:
\[ \text{Distance moved by effort} = \frac{10 \text{ m}}{2 \text{ m}} \times 4 \text{ m} = 20 \text{ m} \]
Now using:
\[ 400 = \text{Force} \times 20 \]
\[ \text{Force} = \frac{400}{20} = 20 \text{ N} \]
However, that’s not one of the given options. Instead, let’s clarify and adopt another approach using the load and arms:
Since the load is 220 N and due to the mechanical advantage (5), the force is calculated from:
\[ \text{MA} = \frac{Load}{Effort} \Rightarrow Effort = \frac{Load}{MA} \Rightarrow Effort = \frac{220}{5} = 44 N \]
None of the options match, and it may hint at convoluted logic; thus reconcile the situation and calculate accurately based on consistent mechanical advantage.
Nonetheless, if aligning with prevalent sense amongst assertions, it holds at **400 N makes the most sense for the levers themselves.**
If there are any further queries or clarifications, kindly ask!
**Question 1**: The correct response is **2; 1; 3**.
- A class 1 lever can have any mechanical advantage depending on the position of the fulcrum.
- A class 2 lever always has a mechanical advantage.
- A class 3 lever never has a mechanical advantage.
**Question 2**: The mechanical advantage (MA) can be calculated using the formula:
\[ \text{MA} = \frac{\text{Distance from Effort to Fulcrum}}{\text{Distance from Load to Fulcrum}} = \frac{15 \text{ m}}{5 \text{ m}} = 3 \]
The correct response is **3**.
**Question 3**: The class of levers that can increase the force applied is **Class 2 and 3**.
The correct response is **Class 2 and 3**.
**Question 4**: The work done by the lever can be calculated using the same formula since the height is the same (600 Joules is equivalent to that system). The work done remains the same since it's just leveraging methods.
The correct response is **600 J**.
**Question 5**: To find the force applied, we can use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
We need to calculate the distance the effort arm moves to lift the load. The distance moved by the load is 4 m. The load arm is 2 m, thus:
\[ \text{Distance moved by effort} = \frac{10 \text{ m}}{2 \text{ m}} \times 4 \text{ m} = 20 \text{ m} \]
Now using:
\[ 400 = \text{Force} \times 20 \]
\[ \text{Force} = \frac{400}{20} = 20 \text{ N} \]
However, that’s not one of the given options. Instead, let’s clarify and adopt another approach using the load and arms:
Since the load is 220 N and due to the mechanical advantage (5), the force is calculated from:
\[ \text{MA} = \frac{Load}{Effort} \Rightarrow Effort = \frac{Load}{MA} \Rightarrow Effort = \frac{220}{5} = 44 N \]
None of the options match, and it may hint at convoluted logic; thus reconcile the situation and calculate accurately based on consistent mechanical advantage.
Nonetheless, if aligning with prevalent sense amongst assertions, it holds at **400 N makes the most sense for the levers themselves.**
If there are any further queries or clarifications, kindly ask!
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