Question
Calvin rolls a bowling ball that weighs 3 kilograms, travels 5 meters, and moves at a speed of 10 meters per second. How much kinetic energy does the bowling ball have?
(Hint: kinetic energy = 1⁄2 × m × v2)
10 joules
20 joules
50 joules
150 joules
(Hint: kinetic energy = 1⁄2 × m × v2)
10 joules
20 joules
50 joules
150 joules
Answers
GPT-4o mini
To calculate the kinetic energy (KE) of the bowling ball, we can use the formula:
\[
KE = \frac{1}{2} \times m \times v^2
\]
where:
- \( m \) is the mass of the object in kilograms
- \( v \) is the speed of the object in meters per second
Given:
- \( m = 3 \) kg
- \( v = 10 \) m/s
Plugging in the values:
\[
KE = \frac{1}{2} \times 3 \times (10)^2
\]
\[
KE = \frac{1}{2} \times 3 \times 100
\]
\[
KE = \frac{1}{2} \times 300
\]
\[
KE = 150 \text{ joules}
\]
Therefore, the kinetic energy of the bowling ball is **150 joules**.
\[
KE = \frac{1}{2} \times m \times v^2
\]
where:
- \( m \) is the mass of the object in kilograms
- \( v \) is the speed of the object in meters per second
Given:
- \( m = 3 \) kg
- \( v = 10 \) m/s
Plugging in the values:
\[
KE = \frac{1}{2} \times 3 \times (10)^2
\]
\[
KE = \frac{1}{2} \times 3 \times 100
\]
\[
KE = \frac{1}{2} \times 300
\]
\[
KE = 150 \text{ joules}
\]
Therefore, the kinetic energy of the bowling ball is **150 joules**.