The mixture of gases used by deep sea divers contains helium, oxygen, and carbon dioxide. What is the pressure of oxygen within the diving tank if the partial pressures of helium and carbon dioxide are 84.0 kPa and 0.900 kPa, respectively? The total pressure of the tank is 101.8 kPa.

186.7 kPa

102.7 kPa

16.9 kPa

1.35 kPa

1 answer

To determine the pressure of oxygen within the diving tank, we can use Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas.

The formula can be expressed as:

\[ P_{\text{total}} = P_{\text{He}} + P_{\text{O}2} + P{\text{CO}_2} \]

Where:

  • \( P_{\text{total}} \) = total pressure of the gas mixture (101.8 kPa)
  • \( P_{\text{He}} \) = partial pressure of helium (84.0 kPa)
  • \( P_{\text{CO}_2} \) = partial pressure of carbon dioxide (0.900 kPa)
  • \( P_{\text{O}_2} \) = partial pressure of oxygen (unknown)

We can rearrange the equation to solve for \( P_{\text{O}_2} \):

\[ P_{\text{O}2} = P{\text{total}} - P_{\text{He}} - P_{\text{CO}2} \] \[ P{\text{O}_2} = 101.8 , \text{kPa} - 84.0 , \text{kPa} - 0.900 , \text{kPa} \]

Now, perform the calculation:

\[ P_{\text{O}2} = 101.8 - 84.0 - 0.900 \] \[ P{\text{O}2} = 101.8 - 84.9 \] \[ P{\text{O}_2} = 16.9 , \text{kPa} \]

Thus, the pressure of oxygen within the diving tank is 16.9 kPa.