Asked by quandale dingle
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Question
A volleyball net post needs a cable to support it. The hook to attach the cable is 4 ft. above the court surface and the hook in the floor is 3 ft. from the base of the post. How long should the cable be? (1 point)
Responses
25 ft
25 ft
2.65 ft
2.65 ft
5 ft
5 ft
4 ft
Question
A volleyball net post needs a cable to support it. The hook to attach the cable is 4 ft. above the court surface and the hook in the floor is 3 ft. from the base of the post. How long should the cable be? (1 point)
Responses
25 ft
25 ft
2.65 ft
2.65 ft
5 ft
5 ft
4 ft
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length of the cable needed to support the volleyball net post, we can use the Pythagorean theorem, as we have a right triangle formed by the height of the hook and the distance from the base of the post to the hook in the floor.
1. The height of the hook above the court surface: 4 ft
2. The distance from the base of the post to the hook in the floor: 3 ft
Using the Pythagorean theorem:
\[
c = \sqrt{a^2 + b^2}
\]
where \( a \) is the height (4 ft) and \( b \) is the distance from the base (3 ft):
\[
c = \sqrt{(4)^2 + (3)^2}
\]
\[
c = \sqrt{16 + 9}
\]
\[
c = \sqrt{25}
\]
\[
c = 5 \text{ ft}
\]
Therefore, the cable should be **5 ft** long.
1. The height of the hook above the court surface: 4 ft
2. The distance from the base of the post to the hook in the floor: 3 ft
Using the Pythagorean theorem:
\[
c = \sqrt{a^2 + b^2}
\]
where \( a \) is the height (4 ft) and \( b \) is the distance from the base (3 ft):
\[
c = \sqrt{(4)^2 + (3)^2}
\]
\[
c = \sqrt{16 + 9}
\]
\[
c = \sqrt{25}
\]
\[
c = 5 \text{ ft}
\]
Therefore, the cable should be **5 ft** long.
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