Question
A triangle is drawn on a coordinate plane. Dilate the figure with a magnitude of 3 in reference to the origin. What are the coordinates of the new vertices of A′B′C′ ? (1 point) Responses A′(1,−2) , B′(3,6) , and C′(9,0) upper A prime left parenthesis 1 comma negative 2 right parenthesis , upper B prime left parenthesis 3 comma 6 right parenthesis , and upper C prime left parenthesis 9 comma 0 right parenthesis A′(−5,−8) , B′(−3,0) , and C′(3,0) upper A prime left parenthesis negative 5 comma negative 8 right parenthesis , upper B prime left parenthesis negative 3 comma 0 right parenthesis , and upper C prime left parenthesis 3 comma 0 right parenthesis A′(−6,−15) , B′(0,9) , and C′(18,−9) upper A prime left parenthesis negative 6 comma negative 15 right parenthesis , upper B prime left parenthesis 0 comma 9 right parenthesis , and upper C prime left parenthesis 18 comma negative 9 right parenthesis A′(−23,−53) , B′(0,1) , and C′(2,−1)
Answers
GPT-4o mini
To dilate a triangle with a magnitude of 3 in reference to the origin, you need to multiply each coordinate of the vertices of the triangle by 3.
Assuming the original vertices of the triangle are:
- A(x₁, y₁)
- B(x₂, y₂)
- C(x₃, y₃)
The new coordinates after dilation will be:
- A′(3x₁, 3y₁)
- B′(3x₂, 3y₂)
- C′(3x₃, 3y₃)
However, you didn't provide the coordinates of the original vertices A, B, and C, so we would need that information to find A′, B′, and C′.
If you provide the original coordinates, I will be able to calculate the coordinates of the new vertices after dilation.
Assuming the original vertices of the triangle are:
- A(x₁, y₁)
- B(x₂, y₂)
- C(x₃, y₃)
The new coordinates after dilation will be:
- A′(3x₁, 3y₁)
- B′(3x₂, 3y₂)
- C′(3x₃, 3y₃)
However, you didn't provide the coordinates of the original vertices A, B, and C, so we would need that information to find A′, B′, and C′.
If you provide the original coordinates, I will be able to calculate the coordinates of the new vertices after dilation.