To solve the inequality \( \frac{1}{3}n + 4.6 \leq 39.1 \), we will first isolate \( n \).
- Subtract \( 4.6 \) from both sides:
\[ \frac{1}{3}n \leq 39.1 - 4.6 \]
- Calculate \( 39.1 - 4.6 \):
\[ 39.1 - 4.6 = 34.5 \]
So, the inequality now is:
\[ \frac{1}{3}n \leq 34.5 \]
- Next, multiply both sides by \( 3 \) to eliminate the fraction:
\[ n \leq 34.5 \times 3 \]
- Calculate \( 34.5 \times 3 \):
\[ 34.5 \times 3 = 103.5 \]
Thus, the inequality simplifies to:
\[ n \leq 103.5 \]
Therefore, all possible values of the number \( n \) are:
\[ n \in (-\infty, 103.5] \]